As you can see in the image I have a few bundles, each with Email ID, I need only ONE which has the biggest ID , is there anyway to filter out only the Biggest one in a filter?
If I am using the Numeric Aggregator, I am losing all my data from the preceding and previous modules
To Sort by ID, you first need to aggregate all the bundles into a single array.
Every result (item/record) from a search/match module will output a bundle. To “combine” them into a single structure, you’ll need to use an aggregator of some sort.
Aggregators are modules that accumulate multiple bundles into one single bundle. An example of a commonly-used aggregator module is the Array aggregator module. The next popular aggregator is the Text Aggregator which is very flexible and has applies to many use-cases.
You can use the built-in function sort on the array, the pick the first (highest) bundle.
e.g.:
{{ first(sort(1.array; "desc"; "id")) }}
For more information, see the function documentation in the Help Center.
Here are some useful links and guides you can use to learn more on how to use the Make platform, apps, and app modules. I found these useful when I was learning Make, and hope they might benefit you too —
parseDate | Tokens for formatDatesamliew – request private consultation
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Thank You 10000000 times
No problem, glad I could help!
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samliew – request private consultation
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Yes something like that, depending on the raw values from your bundle (desc/id).
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