I’m trying to extract the recipient’s email address – however, Gmail keep giving me the email address with an “e:” in front of the email (ex. e:peter@smartpass.app)
Any ideas on how to get rid of this? For instance: Markup 2022-07-11 at 12.39.48.png - Droplr
Here’s some screenshots from my scenario:
Thanks in advance!
Hey!
If it’s always “e:” try using : substring(email,2)
Hmm - it seems like it actually cut off the first 2 characters of the email, but left the “e:”
Hmmm…This is interesting. It’s a bit complicated to help you without actually seeing the scenario.
It’s a bit of a guess, but try using a variable where you simply just extract the variable from gmail like it is(Varaible 1) , and then use a second variable to process Variable 1 with substring.
After that, just use variable 2 as email field.
Cheers.
I think it has something to do that Gmail is giving me a “bundle” - not just a string variable?
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Any other ideas? Nothing seems to be working
^^that is correct
Between your first two modules
You need an iterator
Like this
Recipients (even if there is only 1) is a “collection of objects.”
^^This would be passing a group of recipients
if you put a number between the two halves of the IML it would grab “x” spot in the collection of recipients.
E.G always get first recipients email
I have confirmed with my hubspot.